Question

2x-1/3=x-1/3+1,find the value of x​

Answer 1

Step-by-step explanation:

f 2^(x+1) = 3^(1-x) Then find the value of 'x'?

Let 2^( x + 1 ) - 3^( 1 - x ) = 0 be Equation(1).

Take Logs of both sides of Equation(1).

Log[ 2^( x + 1 ) ] - Log[ 3^( 1- x ) ] = 0 Equation(2).

Rearranging Equation(2).

( x + 1 )Log( 2 ) - ( 1 - x )Log( 3 ) = 0 or

( x + 1 )Log( 2 ) = ( 1 - x )Log( 3 ) or

( x + 1 )/( 1 - x ) = Log( 3 )/Log ( 2 ) or

( x + 1 )/( 1 - x ) = 1.584962501 Equation(3).

Therefore

( x + 1 ) = ( 1.584962501 )•( 1 - x ) or

x + ( 1.584962501x ) = ( 1.584962501 - 1 ) or

( 2.584962501 )x = ( 0.584962501 ) or

x = ( 0.584962501 )/( 2.584962501 ) or

x = 0.2262943856

Answer 2

Answer:

1 is the answer

Step-by-step explanation:

$2x - \frac{1}{3} = x - \frac{1}{3} + 1 \\ \frac{6x - 1}{3} = \frac{3x - 1 + 3}{3} \\ \frac{6x - 1}{3} = \frac{3x + 2}{3} \\ 18x - 3 = 9x + 6 \\ 18x - 9x = 6 + 3 \\ 9x = 9 \\ x = \frac{9}{9} \\ x = 1$

I hope it helps you Mark me as brainlist please please please please please please please please please please please please please please