(2x-1/3x)^2 solve by identity
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Answer:
given:-
(2x-1)3
this is forming an identity
(a-b)3=a3-b3-3ab(a-b)
so
(2x-1)3=(2x)3-(1)3-3×(2x)×(1)(2x-1)
(2x-1)3=8x3-1-6x(2x-1)
(2x-1)3=8x3-1-12x2+6x
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