2x+1/3x=6,find 9x×x + 1/4x×x
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Given,
2x + 1/3x = 6
6x² + 1 = 3x .6
6x² + 1 = 18x
take square both sides,
(6x² + 1)² = 324x²
36x⁴ + 1 + 12x² = 324x²
36x⁴ + 1 = 312x² ---------(1)
now, 9x² + 1/4x² = (36x⁴ + 1)/4x²
put eqn (1)
312x²/4x² = 78
hence, 9x² + 1/4x² = 78
2x + 1/3x = 6
6x² + 1 = 3x .6
6x² + 1 = 18x
take square both sides,
(6x² + 1)² = 324x²
36x⁴ + 1 + 12x² = 324x²
36x⁴ + 1 = 312x² ---------(1)
now, 9x² + 1/4x² = (36x⁴ + 1)/4x²
put eqn (1)
312x²/4x² = 78
hence, 9x² + 1/4x² = 78
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1
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