Question

(2x-1)-(3x²-2x-2)

$(2x - 1) - 3x {}^{2} - 2x - 2$
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Answer 1

Answer:

$(2x - 1) - (3 {x}^{2} - 2x - 2) \\ (2x - 1) - 3 {x}^{2} + 2x + 2 \\ 3 {x}^{2} + 4x + 1 = 0 \\ 3 {x}^{2} + 3x - 1x + 1 = 0 \\ 3x(x + 1) - 1(x + 1) \\ (3x + 1) \: (x + 1) \\ x = - 1 \\ x = \frac{ - 1}{3}$

hope it helps you ✅✅✅