(2x-1/3y)^3 please expand it .
please answer someone
Answers
Answered by
81
(a-b)³ = a³-b³-3ab(a-b)
(2x-1/3y)³
=(2x-1)³/(3y)³
= [8x³-1-3(2x)(1)(2x-1)]/27y³
= (8x³-1-12x²+6x)/27y³
(2x-1/3y)³
=(2x-1)³/(3y)³
= [8x³-1-3(2x)(1)(2x-1)]/27y³
= (8x³-1-12x²+6x)/27y³
Hiteshbehera74:
mark it as brai brainliest if you like it
my method would be lengthy, but it's easy to understand
Answered by
12
Answer: Hi buddy so let us go step by step to get a proper understanding
Step-by-step explanation: Using the identity (a-b)³ = a³-b³-3ab(a-b)
(2x-1/3y)³
=(2x-1)³/(3y)³
= [8x³-1-3(2x)(1)(2x-1)]/27y³
= (8x³-1-12x²+6x)/27y³
we get this result , if helped please keep supporting and mark me brainliest
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