Question

(2x-1/3y)^3 please expand it .
please answer someone

Answer 1

(a-b)³ = a³-b³-3ab(a-b)

(2x-1/3y)³
=(2x-1)³/(3y)³
= [8x³-1-3(2x)(1)(2x-1)]/27y³
= (8x³-1-12x²+6x)/27y³

Answer 2

Answer:  Hi buddy so let us go step by step to get a proper understanding

Step-by-step explanation: Using the identity (a-b)³ = a³-b³-3ab(a-b)

(2x-1/3y)³

=(2x-1)³/(3y)³

= [8x³-1-3(2x)(1)(2x-1)]/27y³

= (8x³-1-12x²+6x)/27y³

we get this result , if helped please keep supporting and mark me brainliest