Question

2x+1, 4x-1, 5x+1, are in arithmetic sequence. Find 'x'.

Answer 1

Answer:

Step-by-step explanation:

B= a +c/2

Then,4x-1=(5x+1)+(2x+1)/2

Gives

2(4x-1)=7x+2 -by simplyfying this

8x-2=7x+2

8x-7x=2+2

Gives x=4

Answer 2

The given question is 2x+1, 4x-1, 5x+1, are in arithmetic sequence

we have to find the value of x.

An arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

Some of the example for arithmetic sequence is a set of odd numbers

set of even numbers.

If three numbers p, q, r jm arithmetic progression then 2q=p+r.

The three numbers mentioned here are

$2 x+ 1 \\ 4x - 1 \\ 5x + 1$

Then by applying rule we get,

$(2x + 1) + (5x + 1) = 2(4 x- 1) \\ 2x + 5x + 1 + 1 = 8x - 2 \\ 7x + 2 = 8x - 2 \\ 7x - 8x + 2 + 2 = 0 \\ - x + 4 = 0 \\ x = 4$

Therefore, the value of x is 4.

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