Question

2x-1÷5x=-1/6 solve the equation nad verify​

Answer 1

$\textbf{\huge{ANSWER:}}$

$\sf{Given\:equation:}$

$\frac{2x - 1}{5x} = \frac{( - 1)}{6}$

Cross multiply the equation. We get :-

=》 12 x - 6 = ( -5x )

Take the constant to the R.H.S. and the variables to the L.H.S. and then solve the formed equation :-

=》 12x + 5x = 6

Now, just subtract the variables :-

=》 17x = 6

Take the ( 17 ) to the R.H.S. and then get the value of the variable ( x ) :-

=》 x = $\frac{6}{17}$

Verification :-

We obtained the value of x = $\frac{6}{17}$

Put the value in the equation :-

$\frac{2x - 1}{5x}$

By putting the value of x in the formula, and then solving it, we get the R.H.S. to be equal to :-

$\frac{-1}{6}$

Thus, Verified!

Our answer now appears to be 100% correct!

Answer 2

2x-1÷5x=-1/6 solve the equation and verify.

Let's solve the question :

$\tt{\frac{2x - 1}{5x} =\frac{- 1}{6}}$

Cross multiply it.. we get :

$\tt {- 5x = 6(2x - 1)}$

Solving it further,  Opening the brackets of R.H.S

$\tt{- 5x =12x - 6}..eq.(1)$

Taking variables and coefficients to one side and the other.

$\tt{6 =12x+ 5x}$

$\tt{17x = 6}$

$\tt{x =\frac{6}{17}}$

Thus, The value of x is 6/17.

How did we find the value of x ?

Firstly, Cross multiplying the L.h.s and R.h.s of the equation.

Then, Solving it further,  Opening the brackets of R.H.S. To solve next, Taking variables and coefficients to one side and the other. Thus , like this we get the value of x.

Value of x is 6/17.