Question

2x+1 /7 +5y-3 /3.
3x+2/2-4y +3/9
solve the problem by using the method of eliminating by equating coefficients ​

Answer 1

2x+1/7+5y=1

3x+1-4y=-1/3

2x+1/7+5y=1

7(2x+1/7+5y)=7(1)

14x+1+35y=7

9(14x+1+35y=7)

126x+9+315y=63. 1@

3x+1-4y=-1/3

3(3x+1-4y)=3(1/3)

9x+3-12y=1

14(9x+3-12y=1)

126x+43-168y=14. 2@

substract 1@ and2@

126x+9+315y=63

126x+43-168y=14

(-) (-) (+) (-)

-34+147y=49

147y=49+34

147y=83

y=83/147