Math, asked by rubykaur82766, 1 year ago

(-2x+1) whole cube =6(x+2)

Answers

Answered by pratapsingh7209
0

Answer:

Step-by-step explanation:

Using identity (a+b)^3 = a^3 + b^3 + 3ab (a+b)

= (-2x)^3 + (1)^3 + 3×(-2x)×1 (-2x + 1) = 6(x + 2)

= -8x^3 + 1 - 6x(-2x + 1) = 6x + 12

= -8x^3 + 1 + 12x^2 - 6x = 6x + 12

= -8x^3 + 12x^2 - 6x + 1 is not equal to 6x + 12

This is ur answer.

ThankQ

@RãßhmîVèrmã.

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