Question

(-2x+1) whole cube =6(x+2)

Answer 1

Answer:

(-2x + 1)³ = 6(x+2)

(-2x + 1)((-2x)²+2(-2x)(1) + (1)²) = 6x + 12

-2x + 1 (4x² -4x + 1) = 6x +12

-8x³ + 8x² - 2x + 4x² - 4x +1 =6x + 12

-8x³ + 12x² - 6x + 1 = 6x + 12

Answer 2

Step-by-step explanation:

${( - 2x + 1)}^{3} = 6(x + 2)$

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab(a + b)$

${( - 2x)}^{3} + {1}^{3} + 3( - 2x)(1)( - 2x + 1) = 6(x + 2)$

$- 8 {x}^{3} + 1 - 6x( - 2x + 1) = 6(x + 2)$

$- 8 {x}^{3} + 1 + 12 {x}^{2} - 6x = 6(x + 2)$

$- 8 {x}^{3} + 12 {x}^{2} - 6x + 1 = 6x + 12$

$- 8 {x}^{3} + 12 {x}^{2} - 12x - 11 = 0$

HOPE THIS ANSWER HELPS YOU ✍✍..

PLEASE MARK IT AS BRAINLIEST...