Question

(2x+1)whole sq.+(x+1)whole sq.=6x+47.......quadratic equation

Answer 1

hope it's helpful.......

Answer 2

The given equation is:
${(2x + 1)}^{2} + {(x + 1)}^{2} = 6x + 47$
Solving the equation we get
$5 {x}^{2} + 6x + 2 = 6x + 47$
Further solving we get
$5( {x}^{2} - 9) = 0$
Therefore
$x = + - 3$