Math, asked by firojkumarsahu99, 8 months ago

(2x+1/x+1)⁴-6(2x+1/x+1)²+8=0​

Answers

Answered by tahseen619
2

Step-by-step explanation:

let,

2x+1/x+1 = m

 {m}^{4}  - 6 {m}^{2}  + 8 = 0 \\  {m}^{4}  - 4 {m}^{2} - 2 {m}^{2}   + 8 \\  {m}^{2} ( {m}^{2}  - 4) - 2( {m}^{2}  - 4) \\ ( {m}^{2}  - 4)( {m}^{2}  - 2)

therefore ,

m²=4 m²= 2

m = +- 2 m²= +-√2

Answered by tiwarisushant790
1

Answer:

2x+1/x+1 = m

\begin{lgathered}{m}^{4} - 6 {m}^{2} + 8 = 0 \\ {m}^{4} - 4 {m}^{2} - 2 {m}^{2} + 8 \\ {m}^{2} ( {m}^{2} - 4) - 2( {m}^{2} - 4) \\ ( {m}^{2} - 4)( {m}^{2} - 2)\end{lgathered}m4−6m2+8=0m4−4m2−2m2+8m2(m2−4)−2(m2−4)(m2−4)(m2−2)

therefore ,

m²=4 m²= 2

m = +- 2 m²= +-√2

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