Question

2x+1÷x^2+1 find the derivative

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Answer 1

Step-by-step explanation:

Given,

$y = \frac{2x + 1}{ {x}^{2} + 1}$

$= > \frac{dy}{dx} = \frac{ (x^{2} + 1) \frac{d}{dx} (2x + 1) - (2x + 1) \frac{d}{dx} (x^{2} + 1)}{( {x}^{2} + 1)^{2} }$

$= > \frac{dy}{dx} = \frac{2( {x}^{2} + 1) - 2x(2x + 1) }{( {x}^{2} + 1)^{2} }$

$= > \frac{dy}{dx} = \frac{2 - 2x}{( {x}^{2} + 1)^{2} }$