Math, asked by nights9, 8 months ago

2x+1/x+3= 3x-5/x-1 solve ​

Answers

Answered by sare83
1

Answer:

x = 2 (or) -7

Step-by-step explanation:

Given that,

(2x+1)/(x+3) = (3x-5)/(x-1)

by cross multiplication method,

(2x+1)(x-1) = (3x-5)(x+3)

⇒ 2x² - 2x + x - 1 = 3x² + 9x - 5x - 15

⇒ 2x² -x - 1 = 3x² + 4x - 15

⇒ (3x² + 4x - 15) - (2x² - x - 1) = 0

⇒ 3x² - 2x² + 4x + x - 15 + 1 = 0

⇒ x² + 5x - 14 = 0

by factorisation method,

⇒ x² + 7x - 2x - 14 = 0

⇒ x(x+7) - 2(x+7) = 0

⇒ (x-2)(x+7) = 0

case-(1):                              Case-(2):

        ⇒ x-2 = 0                           ⇒ x+7 = 0

        ⇒ x = 2                               ⇒ x = -7

∴ x = 2 (or) -7

HOPE THIS WOULD BE HELPFUL FOR YOU

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