Question

(2x-1)(x-3) = (x +4)(x-2)​

Answer 1

Answer:

$2x {}^{2} - 6x - x + 3 = x {}^{2} - 2x + 4x - 8$

$2x {}^{2} - 7x + 3 = x {}^{2} + 2x - 8$

$x {}^{2} - 9x + 11 = 0$

Answer 2

$\tt \huge \underline{answer : - } \\ \\ \sf \huge : \mapsto \: (2x - 1)(x - 3) = (x + 4)(x - 2) \\ \\ \sf \huge : \mapsto \: x(2x - 1) - 3(2x - 1) = x(x + 4) - 2(x + 4) \\ \\ \sf \huge : \mapsto \: {2x}^{2} - x - 6x + 3 = {x}^{2} + 4x - 2x - 8 \\ \\ \sf \huge : \mapsto \: {2x}^{2} - 7x + 3 = {x}^{2} + 2x - 8 \\ \\ \sf \huge : \mapsto \: {2x}^{2} - {x}^{2} - 7x - 2x + 3 + 8 = 0 \\ \\ \sf \huge : \mapsto \: {x}^{2} - 9x + 11 = 0$