Question

(2x_1) (x+3)= (x+4) (x_2)

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Answer 1

Step-by-step explanation:

(2x-1) (x+3) = (x+4) (x-2)

On multiplying the brackets we get,

[2x²+6x-x-3] = [x²-2x+4x-8]

Rearranging the terms,

2x²-x²+6x-x+2x-4x-3+8=0

x²+3x+5=0

Answer 2

Answer:

x²-6x-11

Step-by-step explanation:

2x²+5x-1x-3=x²-2x+4x-8

2x²-4x-3=x²+2x-8

Bringing everything in the left hand side:

2x²-x²-4x+2x-3-8=0

we get

x²-6x-11