(2x-1)(x-3)=(x+5)(x-1)
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(2x - 1)(x - 3) = (x + 5)(x - 1). ⇒ 2x2 - 7x + 3 = x 2 + 4x - 5. ⇒ x2 - 11x + 8 = 0. It is of the form ax 2 + bx + c = 0
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