Question

(2x-1) (x-3) = (x+5) (x-1) Check if there is a quadratic equation​

Answer 1

Answer:

Step-by-step explanation:

(2x-1)(x-3)    = (x+5)(x-1)

2x²-6x-x+3 = x²-x+5x-5

2x²-7x+3    = x²+4x-5

2x²-x²-7x-4x+3+5 = 0

x²-11x+8 = 0

a=1 , b=-11, c=8

√b²-4ac = √[-11²-4×1×8]

             = √121-32

             = √89

here is no square root for b²-4ac, hence we can't get a normal solution for this quadratic equation.