(2x-1)(x-3)=(x+5)(x-1)
check whether the following are quadratic equations
Answers
Answered by
1
Answer:
x
+
3
x
+
2
Explanation:
We require the fractions to have common denominators
multiply the numerator/denominator of
x
−
4
x
−
3
by
(
x
+
2
)
=
2
x
−
1
(
x
−
3
)
(
x
+
2
)
+
(
x
−
4
)
(
x
+
2
)
(
x
−
3
)
(
x
+
2
)
=
2
x
−
1
(
x
−
3
)
(
x
+
2
)
+
x
2
−
2
x
−
8
(
x
−
3
)
(
x
+
2
)
add terms on numerators leaving the denominator
=
x
2
−
9
(
x
−
3
)
(
x
+
2
)
←
difference of squares
=
(
x
−
3
)
(
x
+
3
)
(
x
−
3
)
(
x
+
2
)
←
cancel common factor
=
x
+
3
x
+
2
with restriction
x
≠
3
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