Math, asked by oneworldd20021, 2 months ago

2x-1=√x+5 find the value of x​

Answers

Answered by rohangupta0424
0

Answer:

2x-1=\sqrt{x} +5

2x-\sqrt{x} =6

2x-\sqrt{x} -6=0

2x-3\sqrt{x}+2\sqrt{x}-6=0

2\sqrt{x}(\sqrt{x} -2)+3(\sqrt{x} -2)=0

(2\sqrt{x} +3)(\sqrt{x} -2)=0

\sqrt{x} -2=0\\

\sqrt{x} =2

x=2^2=4

2\sqrt{x} +3=0

2\sqrt{x} =-3

\sqrt{x} =\frac{-3}{2}

x=(\frac{-3}{2})^2=\frac{9}{4}

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