2x - 13/5 - x - 3/11 = x - 9/5 + 1
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⇒ (2x – 13)/5 – (x – 3)/11 = (x – 9)/5 + (1/1)
Since, L.C.M. of denominators 5, 11, 5 and 1 = 55
∴ ((2x – 13)/5) × 55 – ((x – 3)/11) × 55 = ((x – 9)/5) × 55 + (1/1) × 55
⇒ 11(2x – 13) – 5(x – 3) = 11(x – 9) + 55
⇒ 22x – 143 – 5x + 15 = 11x – 99 + 55
⇒ 22x – 5x – 11x = -99 + 55 + 143 – 15
⇒ 6x = 198 – 114
⇒ 6x = 84
⇒ x = 84/6
⇒ x = 14
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