Math, asked by saniaaslam253, 9 months ago

2x = 13 - 5y of
2y = 17- 5x​

Answers

Answered by prustyghanashyam34
0

Answer:

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Answered by PixleyPanda
0

Answer:

Step-by-step explanation:

) 3x – 5y – 4 = 0 and 9x = 2y + 7

By elimination method

3x – 5y – 4 = 0

3x – 5y = 4 ...(i)

9x = 2y + 7

9x – 2y = 7 ... (ii)

Multiplying equation (i) by 3, we get

9 x – 15 y = 11 ... (iii)

9x – 2y = 7 ... (ii)

Subtracting equation (ii) from equation (iii), we get

-13y = 5

y = -5/13

Putting value in equation (i), we get

3x – 5y = 4 ... (i)

3x - 5(-5/13) = 4

Multiplying by 13 we get

39x + 25 = 52

39x = 27

x =27/39 = 9/13

Hence our answer is x = 9/13 and y = - 5/13

By substitution method

3x – 5y = 4 ... (i)

Adding 5y both side we get

3x = 4 + 5y

Dividing by 3 we get

x = (4 + 5y )/3 ... (iv)

Putting this value in equation (ii) we get

9x – 2y = 7 ... (ii)

9 ((4 + 5y )/3) – 2y = 7

Solve it we get

3(4 + 5y ) – 2y = 7

12 + 15y – 2y = 7

13y = - 5

y = -5/13

x = 4 + 5 ( -5/13)/ 3

= 4 - 25/13 / 3

= 4 × 13 - 25/13 / 3

= 27/13×3

= 27/39

= 9/13

Hence we get x = 9/13 and y = - 5/13 again.

(iv) x/2 + 2y/3 = - 1 and x – y/3 = 3

By elimination method

x/2 + 2y/3 = -1 ... (i)

x – y/3 = 3 ... (ii)

Multiplying equation (i) by 2, we get

x + 4y/3 = - 2 ... (iii)

x – y/3 = 3 ... (ii)

Subtracting equation (ii) from equation (iii), we get

5y/3 = -5

Dividing by 5 and multiplying by 3, we get

y = -15/5

y = - 3

Putting this value in equation (ii), we get

x – y/3 = 3 ... (ii)

x – (-3)/3 = 3

x + 1 = 3

x = 2

Hence our answer is x = 2 and y = −3.

By substitution method

x – y/3 = 3 ... (ii)

Add y/3 both side, we get

x = 3 + y/3 ... (iv)

Putting this value in equation (i) we get

x/2 + 2y/3 = - 1 ... (i)

(3+ y/3)/2 + 2y/3 = -1

3/2 + y/6 + 2y/3 = - 1

Multiplying by 6, we get

9 + y + 4y = - 6

5y = -15

y = - 3

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