Question

2x^2+10x=20×(x/3)^2 --- find roots. l will mark as brainliest.​

Answer 1

Answer:

• Roots of Equation are 45 Or 0

Step-by-step explanation:

We are given that :

${\small{\tt{2x^2 + 10x = 20 \bigg( \dfrac{x}{3} \bigg) ^2}}}$

Solving the given equation :

${\implies{\small{\tt{2x^2 + 10x = 20 \bigg( \dfrac{x^2}{9} \bigg) }}}}$

${\small{\tt{\implies{2x^2 + 10x = \dfrac{20x^2}{9}}}}}$

${\small{\tt{\implies{2x^2 + 10x - \dfrac{20x^2}{9} = 0 }}}}$

${\small{\tt{\implies{-2x^2 + 90x = 0}}}}$

${\small{\tt{\implies{-2x(x - 45) = 0}}}}$

${\small{\tt{\implies{x - 45 = 0 \: \: or \: \: - 2x = 0}}}}$

${\small{\tt{\implies{x = 45 \: \: or \: \: x = 0}}}}$

Therefore , Roots of the given Quadratic Equation are :

${\large{\frak{\fcolorbox{skyblue}{skyblue}{x = 45 \ \ OR \ \ x = 0}}}}$