Question

2x^2-10x+k=0 find value of k if equation has real and equal roots

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The value of k is 12.5.

Step-by-step explanation:

Since we have given that

$2x^2-10x+k=0$

If equation has real and equal roots,

$b^2-4ac=0\\\\(-10)^2-4\times 2\times k=0\\\\100-8k=0\\\\100=8k\\\\k=\dfrac{100}{8}\\\\k=12.5$

Hence, the value of k is 12.5.

# learn more:

Find the value of k for which the given equation has real and equal roots : 2x^2 - 10x + k=0......please answer fast

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