Question

2x^2+12x+16 factorise​

Answer 1

$2x^{2} + 12x + 16 = 0 \\ 2 {x}^{2} + 4x + 8x + 16 = 0 \\ (2 {x}^{2} + 4x) + (8x + 16) = 0 \\ 2x(x + 2) + 8(x + 2) = 0 \\ (2x + 8)(x + 2) = 0 \\ (x = - 2)(x = - 4)$

So, The Value Of X Is ( - 2 ) OR X Is ( - 4 )

Answer 2

Answer:

2(x+2)(x+4)

Step-by-step explanation:

2x²+12x+16

2[x²+6x+8]

2[x² + 2x + 4x + 8]

2[x (x + 2) + 4 (x + 2)]

2[(x + 2) (x + 4)]

2(x + 2)(x + 4)