Question

2x^2-15x+22factorize ​

Answer 1

Answer:

First you multiply "A and C" (2 and 22)

2 x 22 = 44 then you have to find the factors of 44 the have a sum that equals -15

Two factors of 44 are -11 and -4 if you add them together, they equal -15 so you put those two factors we just found where -15x usto be. Like this : 2x^2 -4x -11x +22  

after that you distribute: 2x(x-2) -11(x-2)

So you take the '2x' and -11 and put them together to find one of your factors (2x -11) and bring down the (x-2) so your factors are : (2x-11) and (x-2)

Step-by-step explanation:

Answer 2

Answer:

2x²-15x+22=(x-2)(2x-11)

Step-by-step explanation:

2x²-15x+22

=2x²-4x-11x+22

=(2x²-4x)-(11x+22)

=2x(x-2)-11(x-2)

=(x-2)(2x-11)