Question

2x^2-2√2x+1=o what is nature of root and the root

Answer 1

Answer:

Hey Mate!! Let me help you for this question.....

Given Equation:  $2x^{2} -2\sqrt{2}x+1=0$

To find the nature of roots, we need to find the DISCRIMINANT of the equation.

Discriminant (D) =  $b^{2}-4ac$

Here, a = 2, b =  $-2\sqrt{2}$ , c = 1

Therefore the discriminant = $(-2\sqrt{2}) ^{2} -4(2)(1)$

=> D = 8 - 8 = 0

Therefore the nature of the roots is REAL and the roots are EQUAL.

Hope this solution has helped you.....

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Answer 2

Answer:

roots are real and equal

Step-by-step explanation:

because descriminant b² - 4ac

= (-2√2)² — 4(2)(1)

= (8) — 8

= 0

If descriminant (b² - 4ac ) = 0 then roots are real and equal