Question

2x^2-2x+1/2=0.
Please solve this.. ​

Answer 1

[HeY Mate]

$2x {}^{2} - 2x + \frac{1}{2} = 0$

=> Discriminant(D) = b^2 - 4ac

$= ( - 2) {}^{2} -4(2)( \frac{1}{2} ) \\ = 4 - 4 \\ = 0$

=> x = -b + √D / 2a

$= \frac{ - ( - 2) + \sqrt{0} }{2(2)} \\ = \frac{2}{4} \\ = \frac{1}{2}$

=> x = -b - √D / 2a

$= \frac{ - ( - 2) - \sqrt{0} }{2(2)} \\ = \frac{1}{2}$

Hence, value of x is 1/2.

I Hope It Helps You✌️

Answer 2

Answer:

$pls \: like \: my \: answer$

Step-by-step explanation:

Your answer

★ FACTORISATION

2x² - 2x + 1/2 = 0

=> 2x² - x - x + 1/2 = 0

=> x(2x - 1) - 1/2(2x - 1) = 0

=> (2x - 1)(x - 1/2) = 0

Now

2x - 1 = 0

=> 2x = 1

=> x = 1/2

Again,

x - 1/2 = 0

=> x = 1/2

Therefore,

x = 1/2