Question

(2x)² + (2x+10)² = 50
${2x}^{2} + ( {2x + 10)}^{2} = {50}^{2}$
factorisation method​

Answer 1

Answer:

x=-5/3, -5

Step-by-step explanation:

2x^2 + (2x+10)^2=50

2x^2 + (2x)^2 + (10)^2 + 2 (2x) (10)=50

2x^2 + 4x^2 + 100 + 40x = 50

6x^2 + 40x +100 =50

6x^2 + 40x = 50-100

6x^2 + 40x= -50

6x^2 + 40x + 50 =0

6x^2 + 30x + 10x + 50 = 0

6x ( x+ 5) + 10 (x + 5) =0

(6x+10) (x+5) =0

therefore, ,

6x+10 =0

6x = -10

x=-10/6

x = -5/3

and ,

x+5 =0

x= -5