Math, asked by BeingYash, 1 year ago

2x^2 +3 (root5)x +5..............

Answers

Answered by abdul9838

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$\huge \: hola \\ \\ hey \: dude \: here \: is \: ur \: ans \\ \\ \huge \: Answer \\ \\ \\ \\ \underline{Step \: by \: Step \: explaination} \\ \\ \bf \: 2 {x}^{2} + 3 \sqrt{5} x + 5 = 0 \\ \\ \bf \: 2 {x}^{2} + (2 \sqrt{5} + \sqrt{5} )x + 5 = 0 \\ \\ \bf \: 2 {x}^{2} + 2 \sqrt{5} x + \sqrt{5} x + 5 = 0 \\ \\ \bf \: 2x(x + \sqrt{5} ) + \sqrt{5} (x + \sqrt{5} ) = 0 \\ \\ \bf \: (2x + \sqrt{5} )x + \sqrt{5} ) = 0 \\ \\ \bf \: x = - \frac{ \sqrt{5} }{2} \\ \\ \bf \: and \\ \\ \bf \: x = - \sqrt{5}$

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