2x^2 +3 (root5)x +5..............
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Solution
Roots of Polynomial are -√5/2 and -√5.
Step-By-Step Explanation:
Correction : 2x² + 3√5x + 5
Let Polynomial be f(x) = 2x² + 3√5x + 5
Step 1 , Solve Polynomial.
2x² + 3√5x + 5
☞ 2x² + 2√5x + √5x + 5
☞ 2x² + 2√5x + √5x + 5 ☞ 2x(x+√5) + √5(x+√5)
☞ 2x² + 2√5x + √5x + 5 ☞ 2x(x+√5) + √5(x+√5) ☞ (2x+√5) (x+√5)
So, Zeros of Polynomial!
f(x)= 2x+√5. 0r x + √5 = 0
☞ 2x = -√5. 0r x = -√5
☞ x = -√5/2
Therefore, Zeros of Polynomial are -√5/2 and -√5.
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