Question

2x^2/3-x^1/3=28 solve the quadratic equation

Answer 1

Answer:

Let a = x^1/3

2a^2 -a = 28

2a^2 - a -28 = 0

(a-4)(2a +7)=0

a = 4 or -7/2

So

x^(1/3) = 4 or (-7/2)

x = 4^3 or (-7/2)^3 = 64

Answer 2

Step-by-step explanation:

Take x^1/3=t

So your equation becomes

2t²-t=28

2t²-t-28=0

(2t+7)(t-4)=0

t=4

x^1/3=4

x=4³=64

t=-7/2

x^1/3=-7/2

x=-343/8