Question

2x^2+3root5+5 factorize

Answer 1

3(3+√​5)​​​ 

________________. BECAUSE ______


.
(1/12)[24x2 + 10x + 1] = (1/12)[24x2 + 6x + 4x + 1]
                                   = (1/12)[6x(4x+1) + 1( 4x + 1)]
                                   = (1/12)[(4x+1) (6x + 1)]

Answer 2

2x^2 + 3 root 5x + 5
D = b^2 -4 ac = (3 root 5)^2 -4 (2)(5) =45-40 =5
x = (-b+/- root D) / 2 a
x = (-3 root5 +/- root 5)/ 2 (2)
x = (root5) [ -3 +/- 1 ]/4
if positive
x= (root5) [ -3+1]/4 = - root 5 / 2
if negative
x= (root5)[-3-1] /4 = - root 5

so the ANS is (x+root5) ( x+root5/2 ) = 0

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