2x^2+3x+1=0 find the roots of alpha^2 minus beta^2
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- 2x²+3x+1=0
- then 2x²+2x+x+1=0
- 2x(x+1)+1(x+1)=0
- (2x+1)(x+1)=0
- and when 2x+1=0
- then 2x=-1
- & x = -1/2
- or when x+1=0
- then x=-1
then finally X= -1/2 & -1
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