Math, asked by vijayasarathi96, 7 months ago

2x^2+3x+1=0 solve by factorizing​

Answers

Answered by prabhjeet01
3

Step-by-step explanation:

2x²+3x+1=0

2x²+2x+x+1=0

2x(x+1)+1(x+1)

(2x+1)(x+1)

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Answered by borate71
0

Answer:

x=(-1/2,-1)

Step-by-step explanation:

2x²+3x+1=0

2x²+2x+x+1=0

2x(x+1)+1(x+1)=0

(2x+1)(x+1)=0

2x+1=0 or x+1=0

2x=-1 or x=-1

x= -1/2 or x= -1

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