2x^2+3x+1=0 solve by factorizing
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Step-by-step explanation:
2x²+3x+1=0
2x²+2x+x+1=0
2x(x+1)+1(x+1)
(2x+1)(x+1)
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Answer:
x=(-1/2,-1)
Step-by-step explanation:
2x²+3x+1=0
2x²+2x+x+1=0
2x(x+1)+1(x+1)=0
(2x+1)(x+1)=0
2x+1=0 or x+1=0
2x=-1 or x=-1
x= -1/2 or x= -1
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