Question

2x^2+3x+1=0 using formula method​

Answer 1

Answer:

-3 + 6√2

Step-by-step explanation:

a = 2

b = 3

c = 1

x = -b + $\sqrt{b^2 - 4ac }$

  = -3 + $\sqrt{(3)^2 - [(4)(2)(1)]}$

  = -3 + $\sqrt{9 - 8}$

  = -3 + [(3)(2)√2]

  = -3 + 6√2