2x^2+3x-1500=0 solve the equation
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Answered by
1
Answer:
2x^2+3x-1500=0
a = 2; b = 3; c = -1500;
Δ = b2-4ac
Δ = 32-4·2·(-1500)
Δ = 12009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x1=−b−Δ√2ax2=−b+Δ√2a
x1=−b−Δ√2a=−(3)−12009√2∗2=−3−12009√4
x2=−b+Δ√2a=−(3)+12009√2∗2=−3+12009√4
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Answered by
4
Step-by-step explanation:
2x2+3x-1500=0
5x^2-1500=0
5x^2=1500
25x=1500
x=1500/25
x=60
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