Question

(-2x^2-3x+2)÷(x+2)
please do it with long division method.

Answer 1

Answer:

$\frac{-2x^2-3x+2}{x+2}\\= -\frac{\left(2x-1\right)\left(x+2\right)}{x+2}\\= -\left(2x-1\right)\\= -2x+1$

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Answer 2

Step-by-step explanation:

so here is the solutuion for it