2x^2-3x-20 find the factor
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Answered by
1
Step-by-step explanation:
2x² - 3x - 20
2x² - 8x - 5x - 20
2x(x - 4) - 5(x - 4)
(2x - 5) (x - 4)
x = 5/2 , 4
Answered by
0
2x^2-3x-20=0
2x^2-8x+5x-20=0
2x(x-4)+5(x-4)=0
(x-4)(2x+5)=0
x-4=0 2x+5=0
x=4 x=-5/2
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