Question

2x^2+3x=2x^2+4x-6 plzz tell me this answer quickly ​

Answer 1

It looks like x² will go on but it is a linear equation.

$2x^2+3x=2x^2+4x-6$

$2x^2+3x-(2x^2+4x-6)=0$

$2x^2+3x-2x^2-4x+6=0$

$(2-2)x^2+(3-4)x+6=0$

$-x+6=0$

$x=6$

Answer 2

"this answer" fast fast fast