Question

(2x-2)+(3x-3)+(9x-9)=1

Answer 1

Answer:

The complete question:

$(2x-2)+(3x-30+(9x-9)=1$

Find the value of $x$.

The required value of $x=\frac{15}{14}$

Step-by-step explanation:

Algebraic expression:

In mathematics, an expression that incorporates variables, constants, and algebraic operations is known as an algebraic expression (addition, subtraction, etc.). Terms combine to form expressions.

The given expression is:

$(2x-2)+(3x-3)+(9x-9)=1$

All terms are shifted to the left:

$(2x-2)+(3x-3)+(9x-9)-1=0$

All the figures and variables are added together:

$14x-15=0$

We shift every term that contains $x$ to the left and every other term to the right.

$14x=15\\x=\frac{15}{14}$

Therefore, the value of $x=\frac{15}{14}$

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Answer 2

The value of x is 15/14.

Given:

(2x-2)+(3x-3)+(9x-9)=1

To Find:

The value of x.

Solution:

To find the value of x we will follow the following steps:

As given in the question, expression is

( 2x - 2 ) + (3x - 3) + ( 9x - 9 ) = 1

By adding like terms and repeating unlike terms

Like terms are 2x, 3x and 9x.

we get,

2x + 3x + 9x - 2 - 3 - 9 = 1

14x - 14 = 1

14x = 1 + 14

14x = 15

$x = \frac{15}{14}$

Henceforth, the value of x is 15/14.