Math, asked by rajusonawne63080, 3 months ago

2x^2-3x+5=0 by factorization method

Answers

Answered by gauravmali846
0

Step-by-step explanation:

{ \implies \: 2 {x}^{2}  - 3x + 5 = 0} \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: { \implies  \: 2 {x}^{2}  + 2x - 5x  - 5= 0} \:  \:  \:  \:  \:  \:  \:  \:  \\  {\implies2x(x + 1) - 5(x + 1)} \\  \:  \:  \:  {\implies \: (x + 1) \:  \: or \: (2x - 5)} \\ { \implies \: \boxed{x =  - 1} \:  \: or \:  \:  \boxed{x =   {\frac{5}{2}  }}}

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