Question

2x^2+3x+5=0..solve it..​

Answer 1

Step-by-step explanation:

2x² + 3x + 5 = 0

=> a = 2, b = 3 , c = 5

=> x = (-b ± √(b²-4ac) )/2a

=> x = ( -3 ± √(3²-4*2*5) )/2*2

=> x = ( -3 ± √(9-40) )/4

=> x = ( -3 ± √-31 )/4

=> x = (-3 ± i√31)/4

=> x = (-3 + i√31)/4 or (-3 - i√31)/4

Answer 2

Answer:

This is your answer.........xd