Question

2x^2-3x+8 find the value of x​

Answer 1

Answer:

x = 3x -4

Explanation:

2x^2-3x+8 = 0  

2x^2 = 3x-8

2x^2 = 3x-8     (take under root)

2x = 3x-8

x = 3x-8/2         (divide 3x-8 with 2)

x = 3x-4

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