Question

2x^2-3x+k=0 in two roots k=?​

Answer 1

AnsWer :

9 / 8.

Correct QuestioN :

2x² - 3x + k = 0. is a Equation and their both roots are equal so, find the value of k ?

SolutioN :

We have, Equation.

$\tt \dagger \: \: \: \: \: 2 {x}^{2} - 3x + k = 0.$

Compare With General Equation.

$\tt \dagger \: \: \: \: \: a {x}^{2} + bx + c= 0.$

Where as,

• a = 2.
• b = - 3.
• c = k.

→ D = b² - 4ac.

→ D = ( - 3 )² - 4( 2 )( k )

→ D = 9 - 8k.

- Both roots are Equal.

→ D = 0.

→ 0 = 9 - 8k.

→ 9 = 8k.

→ k = 9 / 8.

So, Our Quadratic Equation become,

→ 2x² - 3x + 9 / 8 = 0.

Therefore, the value of k is 9 / 8.

Answer 2

We have, Equation.

\tt \dagger \: \: \: \: \: 2 {x}^{2} - 3x + k = 0.†2x

2

−3x+k=0.

Compare With General Equation.

\tt \dagger \: \: \: \: \: a {x}^{2} + bx + c= 0.†ax

2

+bx+c=0.

Where as,

a = 2.

b = - 3.

c = k.

→ D = b² - 4ac.

→ D = ( - 3 )² - 4( 2 )( k )

→ D = 9 - 8k.

- Both roots are Equal.

→ D = 0.

→ 0 = 9 - 8k.

→ 9 = 8k.

→ k = 9 / 8.

So, Our Quadratic Equation become,

→ 2x² - 3x + 9 / 8 = 0.

Therefore, the value of k is 9 / 8.