Math, asked by purubarapatre1963, 7 months ago

2x^2+3x -k =0 ; x2 x=2​

Answers

Answered by Legend42
2

Answer:

Since both equation are set equal to 0, we can write: x² - 3x + 2 = x² - x - 2

Subtract x² from both sides to get: -3x + 2 = -x - 2

Add 3x to both sides to get: 2 = 2x - 2

Add 2 to both sides to get: 4 = 2x

Solve: x = 2

Similar questions