Question

2x^2+3x+k how to find value of k if roots are real

Answer 1

Hey

Here is your answer,

2x^2 + 3x + k =0

a = 2
b = 3
c = k

b^2 - 4ac = (3)^2 - 4 x 2 x k
9 - 8k = 0
8k = 9
k = 9/8

Hope it helps you!