Math, asked by hr8865514, 7 months ago

(2x^2+3y+3)(2y-3x^2)

Answers

Answered by ruhildivya06
1

Answer:

first step

2x^2(2y-3x^2)

4x^2y -6x^4

second step

3y(2y-3x^2)

6y^2-9yx^2

Third step

3(2y-3x^2)

6y-9x^2

Fourth step

4x^2-6x^4+6y^2-9yx^2+6y-9x^2

-2x^2 + 6y^2-9yx^2+6y-9x^2

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