Question

2x^2-3y=8 express x in terms of y

Answer 1

Step-by-step explanation:

$2 {x}^{2} - 3y = 8 \\ = > 2 {x}^{2} = 8 + 3y \\ = > {x}^{2} = \frac{8 + 3y}{2} \\ = > x = \sqrt{ \frac{8 + 3y}{2} }$

OR,

$2 {x}^{2} - 3y = 8 \\ = > 3y = 2 {x}^{2} - 8 \\ = > y = \frac{2 {x}^{2} - 8}{3}$

Answer 2

Answer:

2 x square -3y= _8

xy= _8+1

xy =_7

I think the answer is -7