Question

2x^2+4√3+6=0 find the roots of the quadratic eqn​

Answer 1

Answer:

The roots of the quadratic equation are $(2\sqrt{3}+3)i$

Step-by-step explanation:

We have been given a quadractic equation(a polynomial of degree 2), we need to find the roots of the equation, since the term with x variable is missing we will be equating the quadratic equation to zero to find the roots of the equation.

$2x^{2} +4\sqrt{3} +6=0\\2(x^{2} +2\sqrt{3} +3)=0\\x^{2} +2\sqrt{3} +3=0\\x^{2} =-(2\sqrt{3} +3)\\x=\sqrt{-(2\sqrt{3} +3)} \\x=(2\sqrt{3}+3)i$

The root of the equation is $(2\sqrt{3} +3)i$